[Originally posted by dave]

> On page 120, the author proposes to find the date of the previous Saturday

> (from today) by subtracting 2 from the date on which Monday of the current

> week falls. On the following page, the author proposes to find the first

> Monday of they year as the Monday during the week containing January 7.

>

> Suppose today is Sunday, January 7. "Monday of the current week" and "the

> Monday of the week containing January 7" must be the same. Call that date

> "mystery Monday." Since today is Sunday, January 7, mystery Monday is either

> January 1 or January 8.

>

> If mystery Monday is January 1, the "previous Saturday" calculation yields

> December 30 (but should yield January 6). If mystery Monday is January 8, the

> "first Monday of the year" calculation yields January 8 (but should yield

> January 1).

Steve,

You're absolutely right. Thanks for pointing out the errors.

In this case, it's the previous Saturday calculation that is wrong. For Sunday

Jan 7th 2000, it yields Dec 30th. Your "mystery Monday" is therefore Jan 1st.

I need to give some thought to fixing the problem.

> Additional erratum:

> If today is Saturday, the "previous Saturday calculation on pages 117-18

> return today, but the calculation on page 121 returns the date 7 days ago.

Right again. In this case the fix is quite simple. Simply add the line

$diff = 7 unless $diff;

once you've calculated $diff.

> The author is correct, as he states on page 121, that "this isn't as simple as

> it sounds." Have I missed something, or has he?

I have. Thanks for being so on the ball

Cheers,

Dave...