396944 (8) [Avatar] Offline
#1
Hello, I would like to ask you, how did you got the result x=6 and y=5 in the figure 4.20? If I put this numbers in the equation, I can't get the right result? 5^2 = 6^3 + 7 % 11 -> 25 = 216 + 7 % 11 -> 25 = 216 + 7 -> 25 = 223.
Where did I made a mistake?

thank you
Miro
Kalle Rosenbaum (19) [Avatar] Offline
#2
396944 wrote:Hello, I would like to ask you, how did you got the result x=6 and y=5 in the figure 4.20? If I put this numbers in the equation, I can't get the right result? 5^2 = 6^3 + 7 % 11 -> 25 = 216 + 7 % 11 -> 25 = 216 + 7 -> 25 = 223.
Where did I made a mistake?


Hi!

I don't think you made any mistake, you just didn't finish your modulo calculations:

5^2 % 11 = (6^3 + 7) % 11 ->
25 % 11 = (216 + 7) % 11 ->
3 = 223 % 11 ->
3 = (20*11+3) %11 ->
3 = 3

So 25 equals 223 in the modulo 11 world.

Thank you so much for buying the MEAP. I hope you find it useful.

/Kalle
396944 (8) [Avatar] Offline
#3
Hello, thank you for a quick answer.
Now it is a clear for me.
It is a congruence modulo A?B(mod C). I calculated it as a classic equation.

Thanks
I'm lookin forward for the next chapters.

Miro
396944 (8) [Avatar] Offline
#4
396944 wrote:Hello, thank you for a quick answer.
Now it is a clear for me.
It is a congruence modulo A?B(mod C). I calculated it as a classic equation.

Thanks
I'm lookin forward for the next chapters.

Miro