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michele.orsini (1) [Avatar] Offline
#1
First of all: Nishant, your book is great and it is a pleasure reading it.
Then:
I found a point that I did not understand in chap 4, in CAutoNativePtr class implementation.

I wonder why operator-> and operator T* are declared static in the above class, I tried to remove the static keyword and the example failed to compile.
In particular, removing static keyword from operator T*, compiler error is:
error C2440: 'return' : cannot convert from 'Native' to 'AutoNativePtr<T> %'
in the "return *this statement" of the operator= member function.

It is "as if" compiler applied operator T* to *this expression, while using the static keyword this does not happen, as if some sort of "precedence" is applied to non static member function to solve a syntactic conflict.

In standard C++, it is frequent to have smart pointer classes with both T* operator and a "return *this" statement in his assignment operator.
Does it means that every time assignment operator of these smart pointer is at work a "nude" pointer is returned and a smart pointer constructor is implicitly invoked?
Can you please shed some light on this point please?
thanks

Michele